6-Bromo-4-phenyl-3,4-dihydroquinolin-2(1H)-one
  -molcms-05142623592D

 18 20  0  0  0  0  0  0  0  0999 V2000
   -2.5981   -0.5000    0.0000 Br  0  0  0  0  0  0  0  0  0  0  0  0
   -1.7321    0.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   -1.7321    1.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   -0.8660    1.5000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.0000    1.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.0000    0.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   -0.8660   -0.5000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.8660   -0.5000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    1.7321    0.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    1.7321    1.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.8660    1.5000    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
    2.5981    1.5000    0.0000 O   0  0  0  0  0  0  0  0  0  0  0  0
    0.8660   -1.5000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.0000   -2.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.0000   -3.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.8660   -3.5000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    1.7321   -3.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    1.7321   -2.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
  1  2  1  0  0  0  0
  2  7  2  0  0  0  0
  2  3  1  0  0  0  0
  3  4  2  0  0  0  0
  4  5  1  0  0  0  0
  5  6  2  0  0  0  0
  6  7  1  0  0  0  0
  6  8  1  0  0  0  0
  8  9  1  0  0  0  0
  9 10  1  0  0  0  0
 10 11  1  0  0  0  0
 11  5  1  0  0  0  0
 10 12  2  0  0  0  0
  8 13  1  0  0  0  0
 13 14  2  0  0  0  0
 14 15  1  0  0  0  0
 15 16  2  0  0  0  0
 16 17  1  0  0  0  0
 17 18  2  0  0  0  0
 18 13  1  0  0  0  0
M  END
>  <ProductName>
6-Bromo-4-phenyl-3,4-dihydroquinolin-2(1H)-one

>  <CASNumber>
94025-76-0

>  <MolecularFormula>
C15 H12 Br N O

>  <MDLNo>
MFCD12031575

>  <MolWt>
302.17

>  <BoilingPoint>


>  <MeltingPoint>


>  <MolFile>


>  <Smiles>
BrC=1C=CC2=C(C1)C(CC(N2)=O)C3=CC=CC=C3

$$$$